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1549-51-5

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1549-51-5 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 1549-51-5 includes 7 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 4 digits, 1,5,4 and 9 respectively; the second part has 2 digits, 5 and 1 respectively.
Calculate Digit Verification of CAS Registry Number 1549-51:
(6*1)+(5*5)+(4*4)+(3*9)+(2*5)+(1*1)=85
85 % 10 = 5
So 1549-51-5 is a valid CAS Registry Number.

1549-51-5Relevant articles and documents

Copper-mediated fluoroalkylation reactions with iododifluoroacetamides: Controlling the selectivity among cross-coupling, intramolecular cyclization, and homocoupling reactions

Zhu, Jieming,Zhang, Wei,Zhang, Laijun,Liu, Jun,Zheng, Ji,Hu, Jinbo

experimental part, p. 5505 - 5512 (2010/11/17)

Cu-mediated fluoroalkylation reactions with iododifluoroacetamides 1 have been systematically investigated. It was found that three types of reactions may coexist in Cu-mediated reactions between iododifluoroacetamides and aryl/alkenyl iodides: cross-coupling, intramolecular cyclization, and homocoupling reactions. The selectivity among these three types of reactions could be controlled by tuning the substituents on the nitrogen atom of iododifluoroacetamides, and/or by removing the cross-coupling reaction partner (aryl/alkenyl halides). The general rule is as follows: (a) in the presence of proper aryl/alkenyl iodides, the cross-coupling products 2 (or 6) are generally formed as the major products; (b) in the absence of aryl/alkenyl iodides, and when R1 = alkyl and R2 = aryl groups, or when R 1 = R2 = aryl groups, the intramolecular cyclization products 3 can be formed predominantly; and (c) in the absence of aryl/alkenyl iodides, and when R1 = R2 = alkyl groups, or when R 1 = H and R2 = alkyl, aryl groups, the homocoupling products 4 can be formed dominantly. Our experimental results also indicate that in many cases when cross-coupling, homocoupling, and intramolecular cyclization reactions coexist in the Cu-mediated reaction system, the reactivity decreases in the following order: cross-coupling > intramolecular cyclization > homocoupling.

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