5627-11-2 Usage
General Description
Hydroxylamine, O,O'-1,2-ethanediylbis- is a chemical compound with the formula (HO)2NCH2CH2NHOH. It is a powerful reducing agent and is commonly used in the synthesis of pharmaceuticals, pesticides, and other organic compounds. It is also used as an intermediate in the production of other chemicals, such as hydroxylamine-O-sulfonic acid. Hydroxylamine,O,O'-1,2-ethanediylbis- is highly reactive and must be handled with caution, as it can react violently with oxidizing agents and should be stored in a cool, dry place away from light and heat sources. Additionally, hydroxylamine, O,O'-1,2-ethanediylbis- poses health hazards and can cause irritation to the skin, eyes, and respiratory system, therefore proper safety measures should be taken when handling this chemical.
Check Digit Verification of cas no
The CAS Registry Mumber 5627-11-2 includes 7 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 4 digits, 5,6,2 and 7 respectively; the second part has 2 digits, 1 and 1 respectively.
Calculate Digit Verification of CAS Registry Number 5627-11:
(6*5)+(5*6)+(4*2)+(3*7)+(2*1)+(1*1)=92
92 % 10 = 2
So 5627-11-2 is a valid CAS Registry Number.
5627-11-2Relevant articles and documents
Oxidation of N,N'-Dialkyl-1,2-bishydroxylamines
Weiss, Randy H.,Furfine, Eric,Hausleden, Edward,Dixon, Dabney White
, p. 4969 - 4972 (2007/10/02)
Oxidation of N,N'-dialkyl-1,2-bishydroxylamines RNHOCH2CH2ONHR gives products that are a function of oxidant.For R = i-Pr (5) and m-chloroperbenzoic acid the products are diisopropyl azo dioxide, HOCH2CH2ONHCH(CH3)2, and ethylene glycol.Product ratios indicate independent oxidation of the two hydroxylamine functions.Na2WO4/H2O2 in D2O gives the azo dioxide, ethylene glycol, and acetone oxime.Oxidation with bromine and 1,4-diazabicyclooctane or tert-butyl hypochlorite and triethylamine gives product ratios that are consistent with two pathways to the bis oxime 7: one that appears to give 7 directly and a second that goes through the monohydroxylamine monooxime 15.It is proposed that the former reaction proceeds through the 1,4,2,3-dioxadiazine ring, which is oxidized quickly to products.Reaction products from the bishydroxylamine with R = CH3 are similar to those with R = i-Pr.