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63789-69-5

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63789-69-5 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 63789-69-5 includes 8 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 5 digits, 6,3,7,8 and 9 respectively; the second part has 2 digits, 6 and 9 respectively.
Calculate Digit Verification of CAS Registry Number 63789-69:
(7*6)+(6*3)+(5*7)+(4*8)+(3*9)+(2*6)+(1*9)=175
175 % 10 = 5
So 63789-69-5 is a valid CAS Registry Number.

63789-69-5Upstream product

63789-69-5Downstream Products

63789-69-5Relevant articles and documents

9-Hydroxydibenzo[b,d]pyrans and intermediates

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, (2008/06/13)

9-Hydroxydibenzo[b,d]pyrans useful as analgesics, hypotensives, immunosuppressants, tranquilizers; as anti-secretory and anti-anxiety drugs; intermediates therefor and derivatives thereof having the formulae STR1 wherein R is hydrogen or alkanoyl having from one to five carbon atoms; R1 is hydrogen, alkanoyl having from one to five carbon atoms or --CO--(CH2)P --NR2 R3 wherein p is 0 or an integer from 1 to 4; each of R2 and R3 when taken individually is hydrogen or alkyl having from one to four carbon atoms; R2 and R3 when taken together with the nitrogen to which they are attached form a 5- or 6-membered heterocyclic ring selected from piperidino, pyrrolo, pyrrolidino, morpholino and N-alkylpiperazino having from one to four carbon atoms in the alkyl group; Each of R4 and R5 is hydrogen, methyl or ethyl; R0 is oxo or alkylenedioxy having from two to four carbon atoms; Z is (a) alkylene having from one to nine carbon atoms; (b) --(alk1)m --X--(alk2)n --wherein each of (alk1) and (alk2) has from 1 to 9 carbon atoms, with the proviso that the summation of carbon atoms in (alk1) plus (alk2) is not greater than 9; Each of m and n is 0 or 1; X is O, S, SO or SO2 ; and W is methyl, phenyl, p-chlorophenyl, p-fluorophenyl, pyridyl, piperidyl, cycloalkyl having from 3 to 7 carbon atoms, or monosubstituted cycloalkyl wherein the substituent is phenyl, p-chlorophenyl or p-fluorophenyl; With the proviso that when W is methyl, Z is --(alk1)m --X---(alk2)n --.

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