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90491-53-5

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90491-53-5 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 90491-53-5 includes 8 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 5 digits, 9,0,4,9 and 1 respectively; the second part has 2 digits, 5 and 3 respectively.
Calculate Digit Verification of CAS Registry Number 90491-53:
(7*9)+(6*0)+(5*4)+(4*9)+(3*1)+(2*5)+(1*3)=135
135 % 10 = 5
So 90491-53-5 is a valid CAS Registry Number.

90491-53-5Relevant articles and documents

Replacing chloride by alkoxide: Cp2Zr(H)OR, searching for alternatives to schwartz's reagent

Perrotin, Philippe,El-Zoghbi, Ibrahim,Oguadinma, Paul O.,Schaper, Frank

, p. 4912 - 4922 (2009/12/25)

Attempts to synthesize zirconocene hydrido alkoxide species, Cp 2Zr(H)OR, via several synthetic pathways consistently failed to yield the targeted complexes, which seem prone to undergo disproportionation into Cp2ZrH2 and

Synthesis and characterization of new alkoxide and aryloxide derivatives of titanium and zirconium. X-ray molecular structure of

Amor, J. I.,Burton, N.C.,Cuenca, T.,Gomez-Sal, P.,Royo, P.

, p. 153 - 160 (2007/10/02)

Lithium or sodium alkoxides MOR (R = CH2CH-CMe2; M = Li 1; Na 2; R = C6F5; M = Li 3) were prepared by reaction of the alcohols with n-butyl lithium or sodium metal in hexane.Reaction of a hexane suspension of 3 with SiClMe3 afforded SiMe3(OC6F5) 4, whereas the reaction of 3 equivalents of C6F5OH with AlMe3 in hexane led to Al(OC6F5)3 5.Compounds 1 or 2 react with one equivalent of *Cl2Me> (Cp* = C5Me5) in toluene to give *ClMe(OCH2CH=CMe2)> 6.Complex 6 reacts with AlEtCl2 to give quantitatively *Cl3>.In the presence of water, the hydrolysis of 6 takes place giving the μ-oxo compound *Cl)(μ-O)>3>. *Cl2Me> reacted with an excess of the alcohol C6F5OH to give *(OC6F5)3> 7. reacted with two equivalents of pentafluorophenol in the presence of aniline to give the dialkoxide 8.When the same reaction was carried out in a 1:1 molar ratio, a mixture of 8 and the chloroalkoxide 9 was obtained.A clean reaction takes place when the μ-oxo compound is treated with two equivalents of pentafluorophenol, leading to the isolation of the alkoxo complex 2(μ-O)> 10.The methylalkoxo derivative 11, was obtained by reaction of with one equivalent of 3.Alternative methods can also be followed to synthesize 8 and 11.The crystal and molecular structure of 8 has been determined by X-ray diffraction methods.The most interesting feature of this structure is the disposition of the (C6F5) ring planes, which are located practically on the reflection plane defined by O(1), Zr(1) and O(1)'. Keywords: Titanium; Zirconium; Alkoxides; X-ray diffraction; Group 4; Cyclopentadienyl

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