98717-39-6Relevant articles and documents
Complexes of Ph2PCH=CH2 with PtX2 (X = Cl, Br, I or Me) or PdX2 (X = Cl, Br or I)
Fontaine, Xavier L. R.,Markham, David P.,Shaw, Bernard, L.
, p. 123 - 129 (1990)
Treatment of Ph2PCH=CH2 with or with , gives cis-, which on treatment with LiBr gives the corresponding dibromide, or with NaI, the corresponding di-iodide.In dichloromethane solution, cis- partially isomerizes to give a cis/trans-mixture.Treatment of with Ph2PCH=CH2 gives cis-.Treatment of with Ph2PCH=CH2 gives a mixture of cis- and trans-, which with LiBr gives a similar mixture of the corresponding dibromides, while reaction with NaI gives trans-. 31P NMR and 1H- and 1H NMR, and IR spectroscopic data are given.
Palladium(II) complexes of diphenylvinyl- and phenyldivinylphosphine
Rahn, Jeffrey A.,Holt, Mark S.,O'Neil-Johnson, Mark,Nelson, John H.
, p. 1316 - 1320 (2008/10/08)
Palladium(II) complexes of the ligands L = Ph2PCH=CH2 and PhP(CH=CH2)2 have been prepared and characterized by elemental analysis, infrared spectroscopy, and 1H, 1H{31P}, 13C{1H}, 31P{1H}, and 1H/13C HETCOR nuclear magnetic resonance spectroscopy. These complexes exist as temperature-dependent equilibrium mixtures of cis and trans isomers in solution. Equilibrium thermodynamics for the isomerization process cis-L2PdX2 ? trans-L2PdX2, determined by variable-temperature 31P{1H} NMR spectroscopy, demonstrate that the cis isomers are in general thermodynamically more stable than the trans isomers. However, the relative isomer stabilities are anion dependent with the trans isomer becoming more stable in the order Cl a vinylphosphine to palladium(II) strongly polarizes the C=C double bond as evidenced by 13C NMR data.
