3,5-Dibenzyloxybenzaldehyde

The Benzaldehyde,3,5-bis(phenylmethoxy)-, with the CAS registry number 14615-72-6, is also known as 3,5-Bis(phenylmethoxy)benzaldehyde. It belongs to the product categories of Aromatic Aldehydes & Derivatives (substituted); Building Blocks for Dendrimers; Functional Materials; Aldehydes; C10 to C21; Carbonyl Compounds. This chemical's molecular formula is C₂₁H₁₈O₃ and molecular weight is 318.37. What's more, its systematic name is 3,5-bis(benzyloxy)benzaldehyde. It is functional materials and for building blocks for dendrimers.

Physical properties of Benzaldehyde,3,5-bis(phenylmethoxy)- are: (1)ACD/LogP: 4.84; (2)# of Rule of 5 Violations: 0; (3)ACD/LogD (pH 5.5): 4.84; (4)ACD/LogD (pH 7.4): 4.84; (5)ACD/BCF (pH 5.5): 2818.82; (6)ACD/BCF (pH 7.4): 2818.82; (7)ACD/KOC (pH 5.5): 10260.15; (8)ACD/KOC (pH 7.4): 10260.15; (9)#H bond acceptors: 3; (10)#H bond donors: 0; (11)#Freely Rotating Bonds: 7; (12)Polar Surface Area: 35.53 Å²; (13)Index of Refraction: 1.622; (14)Molar Refractivity: 95.33 cm³; (15)Molar Volume: 270.5 cm³; (16)Polarizability: 37.79×10^-24cm³; (17)Surface Tension: 47.4 dyne/cm; (18)Density: 1.176 g/cm³; (19)Flash Point: 250 °C; (20)Enthalpy of Vaporization: 77.14 kJ/mol; (21)Boiling Point: 502.4 °C at 760 mmHg; (22)Vapour Pressure: 3.19E-10 mmHg at 25°C.

Preparation: this chemical can be prepared by 3,5-Di(benzyloxy)benzylalkohol at the ambient temperature. This reaction will need reagent pyridinium chlorochromate and solvent CH₂Cl₂ with the reaction time of 1 hour. The yield is about 91%.

Uses of Benzaldehyde,3,5-bis(phenylmethoxy)-: it can be used to produce 1-(3,5-bis(benzyloxy)phenyl)-1-pentanol at the ambient temperature. It will need solvent diethyl ether with the reaction time of 2 hours. The yield is about 92%.

You can still convert the following datas into molecular structure:
(1)InChI: InChI=1S/C21H18O3/c22-14-19-11-20(23-15-17-7-3-1-4-8-17)13-21(12-19)24-16-18-9-5-2-6-10-18/h1-14H,15-16H2
(2)InChIKey: CHUAMRVJSRBRHT-UHFFFAOYSA-N
(3)Canonical SMILES: C1=CC=C(C=C1)COC2=CC(=CC(=C2)C=O)OCC3=CC=CC=C3