Add time:07/19/2019 Source:sciencedirect.com
When Ph2P(S)NHOCOPh labelled with 18O in the CO group (43% isotopic enrichment) reacts with NaOMe in MeOH, the products are unlabelled Ph2P(O)NH2 and labelled PhCO2Me (43% isotopic enrichment). By implication, the intermediate Ph2P(O)NHSCOPh that results from rearrangement (transposition of O and S atoms) has all the label in the CO group and none in the PO group.
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