Add time:07/17/2019         Source:sciencedirect.com

Reactions between bis(trimethylsilyl)methyllithium and the chlorides ECl3 (E = B or Al) yield the di[bis(trimethylsilyl)methyl] derivatives [(Me3Si)2CH]2ECl. The boron compound may be converted by compounds HX (X = OH, NH2, NMe2) in the presence of bases to compounds [(Me3Si)2CH]2BX but the aluminium—carbon bond in [(Me3Si)2CH]2AlCl is easily broken with formation of (Me3Si)2CH2. Bis(trimethylsilylmethyl)aluminium chloride has been made from tris(trimethylsilylmethyl)aluminium and aluminium chloride. Bis(trimethylsilyl)methyllithium reacts with the chlorides ECl2 (E = Cd or Hg) to give the derivatives [(Me3Si)2CH]2E. The cadmium compound is hydrolysed by water or methanol, but not the mercury compound, which reacts with mercury(II) halides to give compounds (Me3Si)2CHHgX (X = Cl, Br or I). Di[1,1′-bis(trimethylsilyl)ethyl]mercury has also been made.

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